Question

Three identical rods of same material are joined to form an equilateral triangle.The temparature of end a and b is maintained constant

Answer 1

Answer:

Temperature of the junction of the two rods is given as

$T = \frac{(T_a + T_b)}{2}$

Explanation:

As we know that all three rods are identical

Now if the temperature of two junctions are made constant so here we will have rate of heat flow along the junction must be constant

so we have

$\frac{kA}{L}(T_a - T) = \frac{kA}{L}(T - T_b)$

so we have

$T_a - T = T - T_b$

$2T = T_a + T_b$

$T = \frac{(T_a + T_b)}{2}$

#Learn

Topic : Heat Transfer

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