Physics, asked by chikkutherattil4718, 11 months ago

Three identicle particle each of mass 1 kg are placed with their centres on a straight line. Their centres are marked A, B and C respectively. The distance of centre of mass of the system from A is.

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Answered by Anonymous
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\huge\underline{\underline{\bf \orange{Question-}}}

Three identicle particle each of mass 1 kg are placed with their centres on a straight line. Their centres are marked A, B and C respectively. The distance of centre of mass of the system from A is.

\huge\underline{\underline{\bf \orange{Solution-}}}

\large\underline{\underline{\sf Given:}}

  • Three identicle particle each of mass 1 kg are placed with their centres on a straight line.

  • Their centres are marked A, B and C

\large\underline{\underline{\sf To\:Find:}}

  • The distance of centre of mass of the system from A is.

Centre of mass

\large{\boxed{\bf \blue{X_{com}=\dfrac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3}} }}

\implies{\sf X_{com}=\dfrac{1×0+1×(AB)+1×(AC)}{1×1×1} }

\implies{\bf \red{ X_{com}=AB+AC}}

\huge\underline{\underline{\bf \orange{Answer-}}}

Distance of centre of mass of the system from A is {\bf \red{AB+AC}}.

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