Three integers are in G.P such that,when 16 is subtracted from third number we get an A.P. If then 2 is subtracted from second number,the resulting numbers again are in G.P.Find the numbers.
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a,ar,ar^2 G.P a,ar,ar^2 - 64 → AP 2ar = a + ar^2 - 64 2r = 1 + r^2 - 64a 64a = r^2 - 2r + 1 a = 64r^2-2r+1 a,ar - 8,ar^2 - 64 → G.P (ar - 8)^2 = ... More
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