Three integers are such that when they are taken in increasing order and multiplied by w2, 3, and 4 respectively, they add up to 74. Find the numbers.
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here is your answer
hope it helps:)-
hope it helps:)-
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Ok so first of all, this question can have many possibilities. I found this answer by trial-and-error method.
So, let the integers be x, y and z.
We get the equation as:
2x + 3y + 4z = 74
So I got one possible answer as
x = 1
y = 4
z = 15
So 2(1) + 3(4) +4(15) = 2 + 12 + 60 = 74
Hope it helps.
So, let the integers be x, y and z.
We get the equation as:
2x + 3y + 4z = 74
So I got one possible answer as
x = 1
y = 4
z = 15
So 2(1) + 3(4) +4(15) = 2 + 12 + 60 = 74
Hope it helps.
mrsanjaysharma:
no
sorry its 8 in the above equation instead of 4
2x+3x+3+4x+8=74
so we get 9x = 74 - 11 = 63
9x+11=74
so, x = 63/9 = 7
9x=74-11=63
so the numbers are 7, 8 and 9
x=63/9=7
ok
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