three iron rod of length 72cm, 128cm and 152 cm are to be cut into pieces of equal length. find the maximum length of each piece that can be cutout such that there is no wastage of rod occurs. Also find the total number of piece that can be cutout.
SUBJECT-MATHEMATICS
Answers
Answered by
1
Answer:
hcf of 72cm, 128cm and 152cm is 8
cut into pieces of equal length = 44
from 72 there is 1.636363636363636363
from 127 there is 2.909090909090909090
from 152 there is 3.454545454545454545
total no of equal pieces = 1.636363636363636363 + 2.909090909090909090 + 3.454545454545454545 = 8
hope this will help you
Answered by
0
Answer:
hcf of 72cm, 128cm and 152cm is 8
cut into pieces of equal length = 44
from 72 there is 1.636363636363636363
from 127 there is 2.909090909090909090
from 152 there is 3.454545454545454545
total no of equal pieces = 1.636363636363636363 + 2.909090909090909090 + 3.454545454545454545 = 8
Step-by-step explanation:
please make me as brainleast
Similar questions