Question

Three labourers worked together for 30 days, in the course of work, all of them remained absent
for few days. One of them was absent for 10 days more than the second labourer and the third
labourer did one-third of the total work. How many days more than the third labourer was the first
one absent ?​

Answer 1

Answer:

answer is 5

Step-by-step explanation:

Let k be the efficiency of A, B and C

And working days are x-10, x, y

According to question

(x-10)k + (x)k = 2/3

(y)k = 1/3

k =1/3y

Putting the vale of k in above equation

(x-10)1/3y + (x)1/3y = 2/3

x-5 = y

y-x = 5