Question

three line AB,CD,and EF meet at point O ,forming angles as shown in the fig.find the value of x,y,z and u​

Answer 1

Answer:

since ab is a staight line

so z+90+50 =180 (linear pair)

z =180 -140

z= 40

also z+y+u =180

so y+u=140

y=140-u.....1

also u+y+x=180....2

also y+x+50=180

so y+x=130

y=130-x......3

Answer 2

Answer:

u=50 ,y=90, x=40,z=40

Step-by-step explanation:

angle u=angle BOD (vertically opposite angles )u=50

y=angleDOF( vertically opposite angles )

Y=90

y+x+u=180 ( linear pair angles )

90+x+50=180

140+x=180

x=180-140

x=40

z=x (vertically opposite angles )

z=40