three lines AB, CD and EF intersect each other at O. If angle ∠AOE = 30°and ∠DOB = 40°, find ∠FOB,∠COA, ∠COE and ∠COF.
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Step-by-step explanation:
As AB is a straight line.
∴∠AOE+∠EOD+∠DOB=180
o
⇒∠EOD=180
o
−30
o
−40
o
⇒∠EOD=110
o
.....(1)
Now, CD and EF intersect each other at point O.
∴∠COF=∠EOD=110
o
[vertically opposite angles]
Therefore, ∠COF=110
o
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