Question

Three liquids of densities p₁, p₂ and p₃ (with P₁> P₂>P₃), having the same value of surface tension T, rise to the same height in three identical capillaries. The angles of contact θ₁, θ₂ and θ₃ obey -
(1) π/2 > θ₁ > θ₂ > θ₃ ≥ 0
(2) 0 ≤ θ₁ < θ₂ < θ₃ < (π/2)
(3) π/2 < θ₁ < θ₂ < θ₃ < π
(4) π > θ₁ > θ₂ > θ₃ > π/2

Answer 1

Answer is 4) π > θ₁ > θ₂ > θ₃ > π/2

Answer 2

Answer:

formula of height of liquid in capillary tube is given by, h=\frac{2Tcos\theta}{\rho rg}

where, T is surface tension, \theta is angle of contact , \rho is density and r is radius of capillary tube.

according to question,

T = constant [ same surface tension ]

r = constant [ identical capillaries ]

h = constant [ same height ]

g always remains constant..

so, cos\theta\propto\rho

here given,

\rho_1 > \rho_2 > \rho_3

so, cos\theta_1 > cos\theta_2 > cos\theta_3

as we know, cosine is decreasing function within 0 to π/2.

so, \theta_3 > \theta_2 > \theta_1

and it is also written as π/2 > θ₁ > θ₂ > θ₃ ≥ 0

Explanation:

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