Question

Three liquids with masses m1, m2, m3 are thoroughly mixed. If their specific heats are s1, s2, s3 and their

temperatures 1, 2, 3 respectively, then the temperature of the mixture is

(A)

1 1 2 2 3 3

1 1 2 2 3 3

s s s

m s m s m s

    

 

(B)

1 1 1 2 2 2 3 3 3

1 1 2 2 3 3

m s m s m s

m s m s m s

    

 

(C)

1 1 1 2 2 2 3 3 3

1 1 2 2 3 3

m s m s m s

m m m

  

  

 

 

(D)

1 1 2 2 3 3

1 1 2 2 3 3

m m m

s s s

  

  ​

Answer 1

Explanation:

For the composite system, energy conservation yields no net energy flow in or out of the system.

Let final temperature be T

Then, heat absorbed by A+heat absorbed by B+heat absorbed by C=0

⇒m1c1(T−T1)+m2c2(T−T2)+m3c3(T−T3)=0

⇒T=m1c1+m2c2+m3c3m1c1T1+m2c2T2+m3c3T3

Answer 2

Answer:

558.8

Explanation:

please see attachment as i could not paste pictures. hope it helps.