Three masses each of 1kg, are placed on the vertices of an equilateral triangle of sides
of length 0.4m. What is the total gravitational potential energy of the configuration?
PLEASE ANSWER URGENTLY. I HAVE MY PHYSICS EXAM TOMORROW
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Answers
Answered by
5
Explanation:
Given Three masses each of 1 kg, are placed on the vertices of an equilateral triangle of sides of length 0.4 m. What is the total gravitational potential energy of the configuration?
Given m = 1 kg and l = 0.4 m
Potential energy between two masses will be – Gm^2 / l
So there are 3 pairs AB, BC and CA
So net potential energy will be 3 x -Gm^2 / l
= - 3 x 6.67 x 10^-11 x 1^2 / 0.4
= - 5 x 10^-10 J
Answered by
0
The gravitational potential energy of the system is:
Explanation:
- Three masses are placed on each vertex of an equilateral triangle.
- They all have equal magnitude of weight as 1 kg.
- The side length of triangle = 0.4 miter
We know the formula to find out the gravitational potential energy (U) as,
We put the value of variables as;
Also, we know that
- U =
This is the gravitational potential energy of the system.
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