Three masses of 5 kg, 3 kg and 2 kg are placed on
a smooth horizontal surface as shown in figure.
When a force of 100 N is applied on it then. Find
1. acceleration
2. T1 and T2
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EXPLANATION
- GIVEN
Masses of block = 5kg,3kg,2kg
Force = 100N
TO FIND ACCELERATION.
Total mass of block = 5 + 3 + 2 = 10kg
F = 100N
F = MA
A = F/M
A = 100/10
A = 10 m/s^2
TO FIND TENSION ON STRING.
THAT IS T1 AND T2.
First we can draw F. B. D of bolck
- CASE 1.
Draw F. B. D of block 5kg
we get,
T2 = 5a
put the value of acceleration
T2 = 5 X 10
T2 = 50N
- CASE 2.
Draw F. B. D of block 2kg
we get,
F - T1 = 2a
100 - T1 = 2 X 10
100 - T1 = 20
T1 = 80N
Therefore,
- ACCELERATION = 10 M/S^2
- TENSION [T1] = 80N
- TENSION [T2] = 50N
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