Question

Three masses of 5 kg ,3kg,2kg are placed on a smooth horizontal surface .when a force of 100 Neuton is applied on it find acceleration of of system .tension t1 and t2

Answer 1

Answer:

i)a=10m/s

ii)t1 and t2  

T1=80

T2=60

Explanation:

i)We Know that F=(all masses)a

=>100=10a

=>10a=100

=>a=100/10

a=10m/s

=>a=10m/s

ii)t1 and t2  

T1=F-2a

=>100-2(10)

=100-20

=80

T2=F-2a

=>80-2(10)

=80-20