Question

Three men A, B and C are standing in a queue. There are five between A and eight between B and C. If there are three ahead of C and twenty-one behind A, what is the minimum number of men in the queue and how​

Answer 1

Answer:

28

Step-by-step explanation:

Three persons A, B, C can be arranged in a queue in six different ways i.e., ABC, CBA, BAC, CAB, BCA, ACB. Butsince there are only 3 persons ahead of C, so C should be in front of the queue. Thus, there are only two possible arrangements i.e., CBA and CAB.

We may consider the two cases as under :

                                        3 8  5  21

Case I : C B A

Clearly, number of persons in the queue= (3 +1+8+1+5+1+21) = 40.

Case II :

Number of persons between A and C= (8 - 6) = 2.Clearly, number of persons in the queue= (3 + 1 + 2 + 1 + 21) = 28.Now, 28 <40. So, 28 is the minimum number of persons in the queue