Three men A,B and C can complete a job in 8,12 and 16 days respectively.A and B work together for 3 days. then B leaves and C joins.In how many days , can A and C finish the work ?
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Answered by
121
Solutions :-
Given :
Three men A, B and C can complete a job in 8, 12 and 16 days respectively.
(A + B + C)'s one day work = 1/8 + 1/12 + 1/16
= (6 + 4 + 3)/48
= 13/48
(A + B)'s one day work = 1/8 + 1/12
= (3 + 2)/24
= 5/24
(A + B)' three days work = (5× 3)/24
= 15/24
Remaining work = 1 - 15/24
= (24 - 15)/24
= 9/24
(A + C)'s one day work = 1/8 + 1/16
= (2 + 1)/16
= 3/16
3/16 work completed in 1 day
1 work completed in 16/3
9/24 work completed in 16/3 × 9/24 = 2 days.
Hence,
A and C completed the work in 2 days.
Given :
Three men A, B and C can complete a job in 8, 12 and 16 days respectively.
(A + B + C)'s one day work = 1/8 + 1/12 + 1/16
= (6 + 4 + 3)/48
= 13/48
(A + B)'s one day work = 1/8 + 1/12
= (3 + 2)/24
= 5/24
(A + B)' three days work = (5× 3)/24
= 15/24
Remaining work = 1 - 15/24
= (24 - 15)/24
= 9/24
(A + C)'s one day work = 1/8 + 1/16
= (2 + 1)/16
= 3/16
3/16 work completed in 1 day
1 work completed in 16/3
9/24 work completed in 16/3 × 9/24 = 2 days.
Hence,
A and C completed the work in 2 days.
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Answered by
2
Answer:
2 Days
Step-by-step explanation:
Given :
Three men A, B and C can complete a job in 8, 12 and 16 days respectively.
(A + B + C)'s one day work = 1/8 + 1/12 + 1/16
= (6 + 4 + 3)/48
= 13/48
(A + B)'s one day work = 1/8 + 1/12
= (3 + 2)/24
= 5/24
(A + B)' three days work = (5× 3)/24
= 15/24
Remaining work = 1 - 15/24
= (24 - 15)/24
= 9/24
(A + C)'s one day work = 1/8 + 1/16
= (2 + 1)/16
= 3/16
3/16 work completed in 1 day
1 work completed in 16/3
9/24 work completed in 16/3 × 9/24 = 2 days.
Hence,
A and C completed the work in 2 days.
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