Question

Three men A, B and C working together can do a job in 6 hours less time then A alone, in 1 hour less time than B alone and in one half the time needed by C when working alone. Then A and B together can do the job in :
[A]\frac{2}{3}\ hour
[B]\frac{3}{4}\ hour
[C]\frac{3}{2}\ hour
[D]\frac{4}{3}\ hour



solution please???​

Answer 1

Time taken by A =x hours.

Therefore taken by A,B and C together = (x-6),

Time taken by B = (x-5).

Time taken by C=2(x-5).

Rate of work of A + Rate of work of B + Rate of work of C = Rate of work of ABC.

[(1/x)+{1/(x−5)}+{1(2/(x−6))}]=1/(x−6)

On Solving=3,40/6

Takingx=3hours

1/[(3/20)+(3/5)]=4/3 hrs

Answer 2

Answer:

3/2 answer

according to question

(a+b+c)-c=1 hr 30 mins...