Three men A, B, and
C working together,
complete a work in
10, 15, and 30 days
respectively. If A and
B left the work 4
days and 3 days
respectively before
the completion of
the work, how many
days in total did it
take to finish the
work?
6
8
9
Answers
Answered by
0
Answer:
8 Days to finish the Work
Step-by-step explanation:
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Answered by
1
Answer:
One day's work of A, B and C = (1/24 + 1/30 + 1/40) = 1/10.
C leaves 4 days before completion of the work, which means only A and B work during the last 4 days.
Work done by A and B together in the last 4 days = 4 (1/24 + 1/30) = 3/10.
Remaining Work = 7/10, which was done by A,B and C in the initial number of days.
Number of days required for this initial work = 7 days.
Thus, the total numbers of days required = 4 + 7 = 11 days.
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