Question

three men A, B, C can complete a job in 8,12,16.A and B can work together in 3 days, then B leaves and c joins.In how many days A and C finish their work.


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Answer 1

Answer:

2 days

Step-by-step explanation:

Given :

Three men A, B and C can complete a job in 8, 12 and 16 days respectively.

(A + B + C)'s one day work = 1/8 + 1/12 + 1/16

= (6 + 4 + 3)/48

= 13/48

(A + B)'s one day work = 1/8 + 1/12

= (3 + 2)/24

= 5/24

(A + B)' three days work = (5× 3)/24

= 15/24

Remaining work = 1 - 15/24

= (24 - 15)/24

= 9/24

(A + C)'s one day work = 1/8 + 1/16

= (2 + 1)/16

= 3/16

3/16 work completed in 1 day

1 work completed in 16/3

9/24 work completed in 16/3 × 9/24 = 2 days.

Hence,

A and C completed the work in 2 days.

Answer 2

A=8,B=12,C=16

A+B=8+12

ANS: 20

20 =3 DAYS

A+C=8+16

ANS: 24

24=2 1/2 DAYS

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