three men can do a piece of work in 4 days how many men can finish it in 3 days
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Let one man's one day's work be x
Let one boy's one day's work be y
According to first condition,
3x+4y=
14
1
.......Equation 1
According to second condition,
4x+6Y=
10
1
.......Equation 2
Multiplying Equation 1 by 4 and Equation 2 by 3,
12x+16y=
14
4
.....Equation 3
12x+18y=
10
3
.....Equation 4
Now solving Equation 3 and 4 simultaneously by substracting Equation 3 by Equation 4,
we get,
∴−2y=
14
4
−
10
3
∴−2y=
140
40−42
∴y=
140
1
Putting the value of y in equation 1, we get,
3x+
140
4
=
14
1
∴x=
70
1
Hence one man's one day work is
70
1
∴ one man completes the whole work in 70 days.
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