Three men have four coats, five waist coats and six caps. In how many
ways can they wear them?
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3
Number of ways in which 3 men can wear 4 coats = P(4,3)=4!
So , total number of ways to wear these clothes = Product of all the above RHS terms which gives the answer 172800.
OR
Number of ways in which 3 Men can wear 4 coats =
4/3−4
=4/1
=1×2×3×4/1
=24 ways
Number of ways in which 3 Men can wear 5 waistcoats =
5/5−3
=5/2
=1×2×3×4×5/1×2
=3×4×5=60 ways
Number of ways in which 3 Men can wear 6 caps
6/6−3
=6/3
=1×2×3×4×5×6/1×2×3
=4×5×6=120 ways
Total number of ways =24 × 60 × 120 =172800
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