Question

Three men, two women and four children are standing in a queue. In how many ways can this group
of people be made to stand in the queue such that the four children always stand together?
a. 288 ways
b. 15120 ways
2880 ways
d. 17280 ways​

Answer 1

288 ways ...

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Answer 2

Answer:

I think the answer is 17280

consider 4 children as one then number of ways is 6! that is 720 ways and then multiply with 4! as children within themselves can be arranged in 4 factorial ways hence answer is 17280