Three metal cube whose edge measure 3cm ,4cm and 5cm resectively are melted to a form a single cube.find its edge. also,find the surface area of the new cube.
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Answered by
3
hey mate
we find volume of 1st small cube
tats ,a^3=27cm^2
2nd one=64cm^2
3rd one=125cm^2
total volume = sum of volume of small cubes
tat is =216cm^3
now to find edge of new cube
216=x^3 so x =6cm
tats the edge
to find its total surface area
which is 6a^2
so by substituting u will get it as 216cm^2
i hope u understood!!
we find volume of 1st small cube
tats ,a^3=27cm^2
2nd one=64cm^2
3rd one=125cm^2
total volume = sum of volume of small cubes
tat is =216cm^3
now to find edge of new cube
216=x^3 so x =6cm
tats the edge
to find its total surface area
which is 6a^2
so by substituting u will get it as 216cm^2
i hope u understood!!
naveen7178:
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Answered by
2
hey mate!
edges of 3cubes=3cm,4cm,5cm
volume of 1st cube=3×3×3=27cm^3
volume of 2nd cube=4×4×4=64cm^3
volume of 3rd cube=5×5×5=125cm^3
volume of single cube formed=volume of 1st cube +volume of 2nd cube+volume of 3rd cube
i.e. side×side×side=27+64+125
side^3=216
side=6cm
surface area of new cube=6×side^2=6×(6)^2
=6×36=216cm^2
edges of 3cubes=3cm,4cm,5cm
volume of 1st cube=3×3×3=27cm^3
volume of 2nd cube=4×4×4=64cm^3
volume of 3rd cube=5×5×5=125cm^3
volume of single cube formed=volume of 1st cube +volume of 2nd cube+volume of 3rd cube
i.e. side×side×side=27+64+125
side^3=216
side=6cm
surface area of new cube=6×side^2=6×(6)^2
=6×36=216cm^2
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