Math, asked by Biswajitbose, 1 year ago

Three metal cubes with edges 6cm, 8 cm and 10 cm respectively melt down and form a single cube. Find the volume of the new cube. Also find the edge of the new cube with its total surface area.

Answers

Answered by SmitButle
5
the volume of cube with edge 6 cm
6×6×6=216
the volume of cube with edge 8 cm
8×8×8=512
the volume of cube with edge 10 cm
10×10×10=1000
therefore,
volume of new cube
216+512+1000=1728 cu cm
edge of new cube
3√1728=12 cm
surface area of cube
6(s×s)
6(12×12)
6×144
864 sq cm

therefore,
the volume of new cube obtained is 1728 cu cm and its edge is 12 cm and surface area is 864 sq cm
Answered by YashP9494
2
Hello friend,
Let 'a' be the side of a cube then it's volume is found as a^3.

Total volume remains constant.
Therefore,
V1 + V2 + V3 = V.

V1 = 6^3 = 216 cm^3.
V2 = 8^3 = 512 cm^3.
V3 = 10^3 = 1000 cm^3.

V = 216 + 512 + 1000 = 1727 cm^3.

Let 'L' be the length of the side of the new cube.
Therefore,
V = L^3 = 1727 cm^3.
L = cuberoot (1727) = 11.998 cm.

Total Surface area = 6×(L)^2.
= 6×(11.998)^2.
= 6×143.94
= 863.67 cm^2.
Hence, the answer!

SmitButle: I m sorry to interfere but your addition is wrong. 216+512+1000=1728 .
SmitButle: therefore your ans that the edge is 11.998 is wrong.its is 12
SmitButle: because of that the surface area also becomes wrong
SmitButle: instead of 863.67 it is complete 864
YashP9494: I am extremely sorry my friend. I realized my mistake later. Unable to change the answer. But the method was correct, I guess.
SmitButle: yes ,it was absolutely correct
SmitButle: method
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