Three metal cubes with edges 6cm, 8 cm and 10 cm respectively melt down and form a single cube. Find the volume of the new cube. Also find the edge of the new cube with its total surface area.
Answers
Answered by
482
volume remains same so
volume of new cube = v1+v2+v3
= 6^3+8^3+10^3
=216+512+1000
=1728
now volume of new cube = a^3= 1728
edge of new cube = a= cuberoot of 1728
a= 12
therefore surface area of new cube = 6 a^2
=6×12^2
=6×12×12
=864 square cm
volume of new cube = v1+v2+v3
= 6^3+8^3+10^3
=216+512+1000
=1728
now volume of new cube = a^3= 1728
edge of new cube = a= cuberoot of 1728
a= 12
therefore surface area of new cube = 6 a^2
=6×12^2
=6×12×12
=864 square cm
Answered by
112
Let volume of cubes be c1,c2,c3,
Then,
Attachments:
Similar questions
Math,
8 months ago
Social Sciences,
8 months ago
Math,
1 year ago
English,
1 year ago
Math,
1 year ago