three metallic cubes with edges 6 cm 8 cm and 10 cm respectively are melted together and form into a single new cube find the volume and surface area of the cube thus
formed
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Volume remains same so
volume of new cube = v1+v2+v3
= 6^3+8^3+10^3
=216+512+1000
=1728
now volume of new cube = a^3= 1728
edge of new cube = a= cuberoot of 1728
a= 12
therefore surface area of new cube = 6 a^2
=6×12^2
=6×12×12
=864 square cm
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Let cubes be c1,c2,c3 respectively
Volume of three cubes =volume of new cube
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