Question

three metallic cubes with edges 6 cm 8 cm and 10 cm respectively are melted together and form into a single new cube find the volume and surface area of the cube thus
formed

Answer 1

Volume remains same so
volume of new cube = v1+v2+v3
= 6^3+8^3+10^3
=216+512+1000
=1728
now volume of new cube = a^3= 1728

edge of new cube = a= cuberoot of 1728

a= 12

therefore surface area of new cube = 6 a^2
=6×12^2
=6×12×12
=864 square cm

Answer 2

Let cubes be c1,c2,c3 respectively

Volume of three cubes =volume of new cube