Three metallic solid cubes whose edges are 3 cm, 4cm, and 5 cm are metalled and formed into a single cube . find the edge of the cube so formed
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8
Volume of cubes = Volume of new cube.
a³+a³+a³ = A³
A³ = 3³+4³+5³
A³ = 27+64+125
A =
![\sqrt[3]{216}](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B216%7D+ "\sqrt[3]{216}")
A = 2*3 = 6cm.
a³+a³+a³ = A³
A³ = 3³+4³+5³
A³ = 27+64+125
A =
A = 2*3 = 6cm.
Answered by
3
hey !!
volume of cube = a³
1: volume of cube +2: volume of cube + 3; volume of cube
=> 3³ + 4³ +5³
=>27 + 64 + 125
=> 216
volume of new cube = a³
=> a³ = 216
=> a =3√216
=> edge of new cube = 6cm
hope it helps !!
#Rajukumar111
volume of cube = a³
1: volume of cube +2: volume of cube + 3; volume of cube
=> 3³ + 4³ +5³
=>27 + 64 + 125
=> 216
volume of new cube = a³
=> a³ = 216
=> a =3√216
=> edge of new cube = 6cm
hope it helps !!
#Rajukumar111
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