Question

Three metallic solid cubes whose edges are 3cm, 4cm & 5cm are melted and formed into a single cube. Find the surface area of cube so formed.

Answer 1

Here is ur answer dear........
the volume of cubes= the volume of the single cube
because if any object is melted and forecast into another form then the volume remains same so,
3^3+4^3+5^3=l^3
27+64+125=l^3
so,
216=l^3
hence the length of the cube is 6cm.
so surface area of the cube is =6*l*l{l is length of the cube
                                               =6*6*6
                                               =216cm.^2
so the total surface area is 216 cm ^2
and the lateral surface area of cube is =4*6*6
                                                           =144cm.^2
 
thanks......................
hope it helps uh @@@@@@@@@@@@@@@@@@@@@@@@@2

Answer 2

Answer:Given, edges of three solid cubes are 3 cm, 4 cm and 5 cm, respectively

. ∴ Volume of first cube = (3)3 = 27 cm3

Volume of second cube = (4)3 = 64 cm3

and volume of third cube = (5)3 = 125 cm3

∴ Sum of volume of three cubes = (27 + 64 + 125) = 216 cm3

Let the edge of the resulting cube = R cm

Then, volume of the resulting cube, R3 =216 ⇒ R = 6 cm

Step-by-step explanation: