Question

three metallic spheres of radii 6cm, 8cm and 10cm respectively are melted together to form a single solid sphere. find the radius of the resulting sphere ​

Answer 1

Answer:

$\huge{\boxed{\sf{RADIUS\:OF\:NEW\:SPHERE=12CM}}}$

Step-by-step explanation:

$\huge{\boxed{\sf{ SOLUTION- }}}$

$volume \: of \: three \: sphere = \frac{4}{3} \pi {r1}^{2} + \frac{4}{ 3} \pi {r2}^{3} + \frac{4}{3} \pi {r3}^{3} \\ v. \: of \: three \: spheres = \frac{4}{3} \pi( {r1})^{3} + ({r2})^{3} + ({r3})^{3} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{4}{3} \pi( {6}^{3} + {8}^{3} + {10}^{3} ) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{4}{ 3} \pi(216 + 512 + 1000) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{4}{3} \pi \times 1728 {cm}^{3} \\again \\ volume \: of \: big \: sphere = \frac{4}{3} \pi \times 1728 {cm}^{3} \\ \frac{4}{3} \pi \times {R}^{3} = \frac{4}{3} \pi \times 1728 \\ {R}^{ 3} = 1728 \\ R= \sqrt[3]{1728} \\ R = 12cm$

$\huge{\boxed{\green{\sf{RADIUS\:OF\:NEW\:SPHERE=12CM}}}}$

Answer 2

Answer:

Hope it helps u

Step-by-step explanation:

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