three metallic spheres of radii 6cm 8cm and 10cm respectively are melted together to form a single solid sphere find the radius of the resulting sphere
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Sphere 1...
r = 6cm
V1 = 4/3×π×r³
= 4/3×22/7×6×6×6
= 4×22/7×72
= 4×22×10.28
= 904.64cm³
Sphere 2...
r = 8cm
V2 = 4/3×π×r³
= 4/3×22/7×8³
= 4/3×22×73.14
= 4×24.38×22
= 2145.44cm²
Sphere 3...
r = 10cm
V3 = 4/3πr³
= 4/3×22/7×1000
= 4/3×22×142.85
= 4×22×47.61
= 4189.68cm³
Volume of new sphere = V1 + V2 + V3
= 904.64 + 2145.44 + 4189.68
= 7239.76cm³
Volume of new sphere = 4/3πr³
7239.76 = 4/3×22/7×r³
7239.76×7×3/4×22 = r³
r³ = 152034.96/88
r³ = 1727.67
r = 11.99 or ~12cm
Thus radius of the new sphere formed is ~12cm or 11.99cm
r = 6cm
V1 = 4/3×π×r³
= 4/3×22/7×6×6×6
= 4×22/7×72
= 4×22×10.28
= 904.64cm³
Sphere 2...
r = 8cm
V2 = 4/3×π×r³
= 4/3×22/7×8³
= 4/3×22×73.14
= 4×24.38×22
= 2145.44cm²
Sphere 3...
r = 10cm
V3 = 4/3πr³
= 4/3×22/7×1000
= 4/3×22×142.85
= 4×22×47.61
= 4189.68cm³
Volume of new sphere = V1 + V2 + V3
= 904.64 + 2145.44 + 4189.68
= 7239.76cm³
Volume of new sphere = 4/3πr³
7239.76 = 4/3×22/7×r³
7239.76×7×3/4×22 = r³
r³ = 152034.96/88
r³ = 1727.67
r = 11.99 or ~12cm
Thus radius of the new sphere formed is ~12cm or 11.99cm
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