Question

Three missiles are fired at a target. If the probability of hitting the target are 4/5, 5/10 & 6/10 respectively & if all the missiles are fired independently. The probability that at least two missiles will hit to the target is:

Answer 1

Answer:

35/50

Step-by-step explanation:

there will be 4 such cases

1: if all missiles hit the target

2: only 1st missile misses the target

3: only 2nd missile misses the target

4: only 3rd missile misses the target

so the probability of first case is 12/50 (by law of multiplication)

the probability of second case will be 3/50 ( by law of multiplication)

the probability of third case will be 12/50 (by law of multiplication)

and the probability of fourth case will be 8/50 (by law of multiplication)

now by law of addition add these possiblities to get the total probability

you will get the answer as 35/50 which is also equal to 7/10

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