Math, asked by abhinavkumar62030, 21 days ago

Three mixture contains milk and water in the ratio 2:3, 4:3 and 1:2 respectively. If one litre of mixtureis taken from each, then find the ratio of milk and water in new mixture.​

Answers

Answered by MoonCrush
50

Answer:

I assume that the required ratio is of water to milk in the final mixture after the first 3 are combined. This is not clear to me in the wording of the question.

Mixture 1 has 3 parts, 1 + 2 = 3

Mixture 2 has 5 parts, 2 + 3 = 5

Mixture 3 has 7 parts, 3 + 4 = 7

The LCM of 3, 5 & 7 is 3 x 5 x 7 = 105

For the solution, assume each mixture contains 105 units.

Mixture 1 ratio is 1:2 or 35:70 and 35 + 70 = 105

Mixture 2 ratio is 2:3 or 42:63 and 42 + 63 = 105

Mixture 3 ratio is 3:4 or 45:60 and 46 + 60 = 105

Sum these units in the final mixture

35+42+46 to 70+63+60

= 122:193 and 122+193 = 315 = 3(105)

The ratio in the mixture is 122:193

as a fraction this is 122/315 = 0.3873

the original mixtures as fractions are 0.33, 0.4 and 0.4286

so 0.3873 looks reasonable.

_________________

hope this helps! <3

 \:  \:

Answered by Ƥяιηcє
5

Answer:

I assume that the required ratio is of water to milk in the final mixture after the first 3 are combined. This is not clear to me in the wording of the question.

Mixture 1 has 3 parts, 1 + 2 = 3

Mixture 2 has 5 parts, 2 + 3 = 5

Mixture 3 has 7 parts, 3 + 4 = 7

The LCM of 3, 5 & 7 is 3 x 5 x 7 = 105

For the solution, assume each mixture contains 105 units.

Mixture 1 ratio is 1:2 or 35:70 and 35 + 70 = 105

Mixture 2 ratio is 2:3 or 42:63 and 42 + 63 = 105

Mixture 3 ratio is 3:4 or 45:60 and 46 + 60 = 105

Sum these units in the final mixture

35+42+46 to 70+63+60

= 122:193 and 122+193 = 315 = 3(105)

The ratio in the mixture is 122:193

as a fraction this is 122/315 = 0.3873

the original mixtures as fractions are 0.33, 0.4 and 0.4286

so 0.3873 looks reasonable.

_________________

hope this helped

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