Question

Three moles of an ideal gas kept at a constant temperature of 300 k are compressed from the volume of 10 litres to 5 litres. Calculate the work done to compress this gas.

Answer 1

answer uploaded in image

Answer 2

The work done to compress this gas is 5187 Joules

Explanation:

To calculate the amount of work done for an isothermal process is given by the equation:

$W=-2.303nRT\log \frac{V_2}{V_1}$

W = amount of work done = ?

n = number of moles = 3 moles

R = Gas constant = 8.314 J/mol.K

T = Temperature of the gas =  300 K

$V_1$ = initial volume = 10 L

$V_2$ = final volume = 5 L

Putting values in above equation, we get:

$W=-2.303\times 3\times 8.314\times 300\times\log \frac{5}{10}=5187J$

The work done to compress this gas is 5187 Joules

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