Question

three natural numbers are in ratio 4:7:11. If the sum of the three numbers is 176, then fined the three number. Also, find the difference between the smallest and the largest of three numbers

Answer 1

Step-by-step explanation:

three no.s are 4x, 7x, 11x

4x+11x+7x = 176

22x=176

x= 8

3 no.s are 32, 56, 88

88-32=56

Answer 2

Question

Three natural numbers are in ratio 4:7:11. If the sum of the three numbers is 176, then find the three number. Also, find the difference between the smallest and the largest of three numbers

Answer

$\bf ~ Given:-$

$\rm ~ Ratio~of~three~natural~numbers=4:7:11$

$\rm ~ Sum~of~three~natural~numbers=176$

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$\bf ~ To~Find: The~ three~numbers$

$\bf~And~the~difference~between~the~ smallest~and~largesr~numbers$

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$\bf ~Let's~Calculate$

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$\tt ~Let~the~first~number~be~4x$

$\tt ~Let~the~second~number~be~7x$

$\tt ~And~the~third~number~be~11x$

‎

$\bf ~According~to~the~question$

$\bf ~ 4x + 7x + 11x = 176$

$\bf ~ \implies 4x + 7x + 11x = 176$

$\bf ~ \implies 11x + 11x = 176$

$\bf ~ \implies 2×11x = 176$

$\bf ~ \implies 22x = 176$

$\bf ~ \implies x = \frac{176}{22}$

$\bf ~ \implies x = 8$

$\tt ~The~first~number~=~4x$

$\tt ~~~~~~~~~~~~~~~~~~~~~~~=~4×8$

$\bf ~The~first~number~=~32$

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$\tt ~The~second~number~=~7x$

$\tt ~The~second~number~=~7×8$

$\bf ~The~second~number~=~56$

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$\tt ~The~third~number~=~11x$

$\tt ~The~third~number~=~11×8$

$\bf ~The~third~number~=~88$

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$\bf~The~difference~between~the~ smallest~and~largest~number=88-56$

$\bf~\therefore \: The~difference~between~the smallest~and~largesr~number=32$