Question

three naturalnumbers are such that the first number is the average of the other two. also the sum of two of these numbers is thevalue of the largest number. find the smallest number if the largest number is15

Answer 1

Answer:

Lets try to find the answer.

Step-by-step explanation:

Let, first number be x.

Let, second number and the largest number be n.

Let, third number be m.

According to the question,

First number is the average of two number.

=> x = n + m

2

=> 2x = n + m

=> 2x - m = n....................................(1)

=> n = x + m......................................(2)

From equation no. 1 and 2,

2x - m = n

+ x + m = n

3x = 2n....................................(3)

=> n = 15 ( Given in question )

Put the value of n in 3rd equation.

=> 3x = 2n

=> 3x = 2 * 15

=> x = 30\3

=> x = 10. Answer.

Similarly, put the value of x in 2nd equation.

=> n = x + m

=> 15 = 10 + m

=> 15 - 10 = m

=> m = 5. Answer.

So, the first number is 10.

the second number is 15.

the third number is 5.

Smallest number is 5. Ans.

I hope it will help you.

Thank you.