Question

three no. are in a ratio of 2 3 4 if their cube is 33125 find the no.​

Answer 1

Appropriate Question:

There numbers are in the ratio 2 : 3 : 4. If their sum of cube is 33957. Find the numbers.

Solution :-

→ 1st number : 2nd number : 3rd number

Assumption: Let us assume the the three numbers as 2x, 3x and 4x.

According to the Question :

→ (2x)³ + (3x)³ + (4x)³ = 33957

→ 8x³ + 27x³ + 64x³ = 33957

→ 99x³ = 33957

→ x³ = 33957/99

→ x³ = 343

Now, taking out the square root,

→ x³ = ∛343

→ x = 7

So, the numbers are :-

→ 2x = 2 × 7 = 14

→ 3x = 3 × 7 = 21

→ 4x = 4 × 7 = 28

Therefore, the numbers are 14, 21 and 28.

Answer 2

$\huge\mathbb\fcolorbox{Green}{violet}{♡correct \: Question}♡$

There numbers are in the ratio 2 : 3 : 4. If their sum of cube is 33957. Find the numbers.

$\huge\mathbb\fcolorbox{Green}{violet}{♡solution}♡$

Let the unknown number be x

The ratio becomes 2x:3x:4x

(2x)³+(3x)³+(4x)³=33957

8x³+27x³+64x³=33957

99x³=33957

x³=33957/99

x³=343

x=cube root 343

x=7

2x=2×7=14

3x=3×7=21

4x=4×7=28

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