Question

three no. are in Ap if the sum of these numbers is 27 and their product is 648 find the number. ........plzz... solve it fast its urgent.....

Answer 1

Hey !!!

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Here is your answer :
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Let the numbers be a - d , a , a + d

So! According to the question

a - d + a + a + d = 27

3a = 27

a = 9

So first term = 9

now

a - d × a × a + d = 648

9 - d × 9 × 9 + d = 648


( 9 - d ) ( 9 + d ) = 648 /9

81 - d2 = 72

9= d2

d = 3

So common difference is 3

So
the number are

a - d = 9 - 3 = 6

a = 9

a + d = 9 + 3 = 12

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Hope it's helpful and correct !!!!

Answer 2

Hey!!!!
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Here is your answer!!!!!
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Let three no. = a-d,a,a+d
sum =a-d+a+a+d=27
3a=27
a=9
product= (a-d)(a)(a+d)=648
648 =a^2-da(a+d)
648 =a^3+a^2d-da^2-d^2a
648 =9^3+9^2×d-d×9^2×-d^2×9
648=729+81d-81d-9d^2
648-729=-9d^2
-81=-9d^2
81/9=d^2
9=d^2
3=d
numbers = a-d =9-3=6
a=9
a+d =9+3=12
numbers = 6,9,12
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I hope it will help you!!!!