Three no. Are in AP whose sum is 30 and product is 910,Then the gretest no. AP
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let 'a' be the first number and 'd' be the common difference.
now as given :
a+(a+d)+(a+2d) = 30 => a+d = 10
and a(a+d)(a+2d) = 910
solving both equations, we get either (a=13 and d = -3) or (a=7 and d=3) in both cases the greatest number in AP is "13".
now as given :
a+(a+d)+(a+2d) = 30 => a+d = 10
and a(a+d)(a+2d) = 910
solving both equations, we get either (a=13 and d = -3) or (a=7 and d=3) in both cases the greatest number in AP is "13".
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