Math, asked by djswami, 1 year ago

three no are in the ratio of 2:3:4.the sum of their cubes are 33957 find the numbers

Answers

Answered by jashmin63
4
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Answered by DangerousBomb
4

\huge{\underline{\bigstar{\sf{solution!!}}}}

The 3 numbers are : 0.3,0.45,0.6

⇛The question says there are three numbers but with a specific ration what that means in that once we pick one of the numbers the other two are know to us through the rations we can therefore replace all 3 of the numbers with a single variable:

2: 3: 4 ⇛ 2x × 3x × 4x

⇒now, no Matter what we chose for c we get the three numbers into the ratios specified we are also told the sum of the cubes of these three numbers which can write :

({2x})^{3} + ({3x})^{3} + ({4x})^{3} = 0.334125

⇛Disturbing the powers across the fact is using

 ({a×b})^{c} = {a}^{c} {b}^{c} we\: get :

 {8x}^{3}+ {27x}^{3} + {64x}^{3} = {99x}^{3} = 0.334125

 {x}^{3} = \frac{0.334125}{99} = 0.003375

 {x}^{3} = \sqrt[3]{0.003375} = 0.15

⇛So the 3 numbers are

 2×0.15, 3×0.15, 4×0.15

 0.3,0.45,0.6

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