Question

Three number are in AP such that their sum is 24 and product of first and last term is 39

Answer 1

Answer:

3, 8, 13

3, 8, 13or

3, 8, 13or13, 8, 5

Step-by-step explanation:

let the ap be

a - d, a, a + d

Given

$a - d + a + a + d = 24$

$3a = 24$

$a = 8$

Also

$(a - d)(a + d) = 39$

${a}^{2} - {d}^{2} = 39$

$64 - {d}^{2} = 39$

${d}^{2} = 25$

$d = 5 \: or \: - 5$

The AP is

3, 8, 13

or

13, 8, 5

Hope it helps

Answer 2

13 ,8 and 5 is UR ANSWER DUDE......❤❤❤❤...