Question

Three number are in ap whose sum is 33 and product is 792 then the smallest number from this number is

Answer 1

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Answer 2

Answer:

Let a-d, a, a+d be the 3 numbers in AP.

Sum = a-d+a+a+d = 33

3a = 33

a = 11

Product, (a-d)a(a+d) = 792

(11-d)11(11+d) = 792

121-d² = 792/11

121-d² = 72

121-72 = d2

So d² = 49

d = ±7

So 4, 11, 18 or 18, 11, 4 are the numbers.

Smallest number is 4.