Question

three number are in continued proportion whose mean in continued proportion is 12 and the sum of the remaning two numbers is 26 then find these number​

Answer 1

Answer:

Solution Show Solution. Let the remaining two numbers be x and y. So, the numbers x, 12, y are in continued proportion.

Answer 2

⭐solution⭐

let, 12 the mean proportional of x and 26 - x

from given condition

${12}^{2} = x(26 - x)$

$144 = 26 - {x}^{2}$

${x}^{2} - 26x + 144 = 0$

${x}^{2} - 18x \: - 18x + 144 = 0$

$x(x - 18) - 8(x - 18) = 0$

$(x - 18)(x - 8) = 0$

$x - 18 = 0 \: or \: x - 8 = 0$

$therefore \: . \: x = 18 \: or \: x = 8$

answer

The required number are 18 , 12 , 8 or 8 , 12 , 18