Three number are in ratio of 4:5:6.lf the sum of the largest and the smallest equal the sum of the third and 55,find the sum.
Answers
Answered by
44
HEY MATE
UR ANSWER IS
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let the common multiple be x
the numbers will be 4 x , 5 x , 6 x
4 x + 6 x = 5 x + 55
10 x = 5 x + 55
5 x = 55
x = 11
so the nubers are
44 , 55 , 66
Their Sum is
44 + 55 + 66 = 165
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THANK UHHH
AdityaRocks1:
Good elaboration Divya. !! ✌✌
Answered by
70
Three number are in ratio of 4:5:6.
Common Multiple be 'x'
so the numbers will be 4x,5x,6x
if the sum of the largest and the smallest equal the sum of the third and 55
4x + 6x = 5x + 55
10x = 5x + 55
10x - 5x = 55
5x = 55
x = 55/5
x = 11
..So the numbers are
4x,5x,6x
4(11),5(11),6(11)
44,55,66
Their Sum is
44 + 55 + 66 = 165
Common Multiple be 'x'
so the numbers will be 4x,5x,6x
if the sum of the largest and the smallest equal the sum of the third and 55
4x + 6x = 5x + 55
10x = 5x + 55
10x - 5x = 55
5x = 55
x = 55/5
x = 11
..So the numbers are
4x,5x,6x
4(11),5(11),6(11)
44,55,66
Their Sum is
44 + 55 + 66 = 165
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