Math, asked by mandurizvi8320, 1 year ago

Three number are in ratio of 4:5:6.lf the sum of the largest and the smallest equal the sum of the third and 55,find the sum.

Answers

Answered by Anonymous
44

HEY MATE

UR ANSWER IS

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let the common multiple be x

the numbers will be 4 x , 5 x , 6 x

4 x + 6 x = 5 x + 55

10 x = 5 x + 55

5 x = 55

x = 11

so the nubers are

44 , 55 , 66


Their Sum is

44 + 55 + 66 = 165

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THANK UHHH



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Answered by RohitSaketi
70
Three number are in ratio of 4:5:6.

Common Multiple be 'x'

so the numbers will be 4x,5x,6x

if the sum of the largest and the smallest equal the sum of the third and 55

4x + 6x = 5x + 55

10x = 5x + 55

10x - 5x = 55

5x = 55

x = 55/5

x = 11

..So the numbers are

4x,5x,6x

4(11),5(11),6(11)

44,55,66

Their Sum is

44 + 55 + 66 = 165

RohitSaketi: oh thanks \(^o^)/
AdityaRocks1: mast bhai !!!
RohitSaketi: Thanks bhai
taniya55555: awesome bhaiya
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