Math, asked by Nishtha1011, 4 months ago

Three number are in the ratio 1:2:3 and the sum of their cubes is 288. Find those numbers.​

Answers

Answered by pragatifzdtiwari
1

Answer:

2 4 6

Step-by-step explanation:

Three numbers are in the ratio 1:2:3

Let say numbers are

N  , 2N  & 3N

sum of their cubes is 288

=> N³ + (2N)³ + (3N)³ = 288

=> N³ + 8N³ + 27N³ = 288

=> 36N³ = 288

=> N³ = 8

=> N³ = 2³

=> N = 2

so three numbers are

2 , 2*2  , 3 * 2

= 2 , 4 , 6

Answered by 16029
0

Answer:

2,4,6

Step-by-step explanation:

Three numbers are in the ratio 1:2:3

Let say numbers are

N  , 2N  & 3N

sum of their cubes is 288

=> N³ + (2N)³ + (3N)³ = 288

=> N³ + 8N³ + 27N³ = 288

=> 36N³ = 288

=> N³ = 8

=> N³ = 2³

=> N = 2

so three numbers are

2 , 2*2  , 3 * 2

= 2 , 4 , 6

Hope you will mark me:)

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