Question

Three number are in the ratio 3:4:5 .the sum of their cube is 27000.find the number

Answer 1

Hey! Here is ur answer...

Let the nos. be 3x, 4x, 5x

So, (3x)^3 + (4x)^3 + (5x)^3 = 27000
27x^3 + 64x^3 + 125x^3 = 27000
216x^3 = 27000
x^3 = 27000 / 216
x^3 = (30 / 6) ^3
=> x = 30 / 6

So, the nos. are :-
1) 3x = 3*30/6 = 15
2) 4x = 4*30/6 = 20
3) 5x = 5*30/6 = 50/3

Hope this helps u... Plz mark it as brainliest... :)

Answer 2

Hey! Here is ur answer...

Let the nos. be 3x, 4x, 5x

So, (3x)^3 + (4x)^3 + (5x)^3 = 27000

27x^3 + 64x^3 + 125x^3 = 27000

216x^3 = 27000

x^3 = 27000 / 216

x^3 = (30 / 6) ^3

=> x = 30 / 6

So, the nos. are :-

1) 3x = 3*30/6 = 15

2) 4x = 4*30/6 = 20

3) 5x = 5*30/6 = 25