Question

three number are in the ratio 3 ratio 4 ratio 5 if the sum of largest and the smallest number exceeds the third number by 64 find the number

Answer 1

Let the three numbers be 3x,4x and 5x

According to the question

5x+3x = 4x + 64

8x-4x = 64

4x = 64

x = 64/4

x = 16

=> 3x = 3×16 = 48

=> 4x = 4×16 = 64

=> 5x = 5×16 = 80

Answer 2

Answer:

Step-by-step explanation:

5x+3x=4x+64

8x-4x=64

4x=64

X=64/4

X=16

3×16=48

4×16=64

5×16=80

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