Question

Three number are in the ratio of 2:3:4 The sum of their cubes in 334125.Find the number ​

Answer 1

Answer:

Answer

Suppose the numbers = 2z, 3z, 4z

Suppose the numbers = 2z, 3z, 4zGiven, the sum of their cubes = 0.334125

Suppose the numbers = 2z, 3z, 4zGiven, the sum of their cubes = 0.334125As per question,

Suppose the numbers = 2z, 3z, 4zGiven, the sum of their cubes = 0.334125As per question,(2z)3+(3z)3+(4z)3=0.334125

Suppose the numbers = 2z, 3z, 4zGiven, the sum of their cubes = 0.334125As per question,(2z)3+(3z)3+(4z)3=0.334125or 8z3+27z3+64z3=0.334125

Suppose the numbers = 2z, 3z, 4zGiven, the sum of their cubes = 0.334125As per question,(2z)3+(3z)3+(4z)3=0.334125or 8z3+27z3+64z3=0.334125or 99z3=0.334125

Suppose the numbers = 2z, 3z, 4zGiven, the sum of their cubes = 0.334125As per question,(2z)3+(3z)3+(4z)3=0.334125or 8z3+27z3+64z3=0.334125or 99z3=0.334125or z3=0.334125÷99

Suppose the numbers = 2z, 3z, 4zGiven, the sum of their cubes = 0.334125As per question,(2z)3+(3z)3+(4z)3=0.334125or 8z3+27z3+64z3=0.334125or 99z3=0.334125or z3=0.334125÷99x3=990.334125=0.003375

Suppose the numbers = 2z, 3z, 4zGiven, the sum of their cubes = 0.334125As per question,(2z)3+(3z)3+(4z)3=0.334125or 8z3+27z3+64z3=0.334125or 99z3=0.334125or z3=0.334125÷99x3=990.334125=0.003375x3=10000003375

Suppose the numbers = 2z, 3z, 4zGiven, the sum of their cubes = 0.334125As per question,(2z)3+(3z)3+(4z)3=0.334125or 8z3+27z3+64z3=0.334125or 99z3=0.334125or z3=0.334125÷99x3=990.334125=0.003375x3=10000003375x=310×10×10×10×10×1015×15×15=10×10×1015=0.015

Suppose the numbers = 2z, 3z, 4zGiven, the sum of their cubes = 0.334125As per question,(2z)3+(3z)3+(4z)3=0.334125or 8z3+27z3+64z3=0.334125or 99z3=0.334125or z3=0.334125÷99x3=990.334125=0.003375x3=10000003375x=310×10×10×10×10×1015×15×15=10×10×1015=0.015Hence, the required numbers are

Suppose the numbers = 2z, 3z, 4zGiven, the sum of their cubes = 0.334125As per question,(2z)3+(3z)3+(4z)3=0.334125or 8z3+27z3+64z3=0.334125or 99z3=0.334125or z3=0.334125÷99x3=990.334125=0.003375x3=10000003375x=310×10×10×10×10×1015×15×15=10×10×1015=0.015Hence, the required numbers are2×0.015=0.03

Suppose the numbers = 2z, 3z, 4zGiven, the sum of their cubes = 0.334125As per question,(2z)3+(3z)3+(4z)3=0.334125or 8z3+27z3+64z3=0.334125or 99z3=0.334125or z3=0.334125÷99x3=990.334125=0.003375x3=10000003375x=310×10×10×10×10×1015×15×15=10×10×1015=0.015Hence, the required numbers are2×0.015=0.033×0.015=0.045

Suppose the numbers = 2z, 3z, 4zGiven, the sum of their cubes = 0.334125As per question,(2z)3+(3z)3+(4z)3=0.334125or 8z3+27z3+64z3=0.334125or 99z3=0.334125or z3=0.334125÷99x3=990.334125=0.003375x3=10000003375x=310×10×10×10×10×1015×15×15=10×10×1015=0.015Hence, the required numbers are2×0.015=0.033×0.015=0.0454×0.015=0.06

Suppose the numbers = 2z, 3z, 4zGiven, the sum of their cubes = 0.334125As per question,(2z)3+(3z)3+(4z)3=0.334125or 8z3+27z3+64z3=0.334125or 99z3=0.334125or z3=0.334125÷99x3=990.334125=0.003375x3=10000003375x=310×10×10×10×10×1015×15×15=10×10×1015=0.015Hence, the required numbers are2×0.015=0.033×0.015=0.0454×0.015=0.06Explanation:

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