Three number are is AP The sum of 3 number is 24 and their product is504 find the number
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Step-by-step explanation:
let a-d, a, a+d be the numbers in AP
sum
a-d + a + a+d = 24
3a = 24
a= 8. ----------(1)
product
(a-d)(a)(a+d) = 504
a(a²-d²) = 504
from (1) a= 8
8 ( 8²-d²) = 504
64-d² = 504/8
64-d² = 63
64-63 = d²
d = ± 1
if d = +1
a-d , a , a+d => 8-1, 8 ,8+1
=> 7,8,9
if d = -1
a-d , a , a+d => 8-(-1) , 8 , 8+(-1)
=> 9,8,7
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