Question

Three number whose sum is 4 are in ap if product of first and third term exceeds the second number by 6 then find numbers

Answer 1

Let the numbers be a-d,a,a+d,where 'a' is the first term and d is the common difference .So,

a-d+a+a+d=4

a=4/3

Then,{a-d}×{a+d}+6=a, from above we have a=4/3 u will get d thus the A.P.