Three numbera are in the ratio 2:3:5. Sum of their cubes is 54880 .what are the numbers?
Plzzz answer with steps
Answers
Answered by
3
Take the sum of ratios =2+3+5
=10
Divide the cubes by the sum=54880/10
=5488
Multiply it by the no.s like 2×5488=10976
3×5488=16464
5×5488=27440
=10
Divide the cubes by the sum=54880/10
=5488
Multiply it by the no.s like 2×5488=10976
3×5488=16464
5×5488=27440
Answered by
5
ALOHA , SAT SRI AKAL , NAMASTE....My dear frnd☺
Here is ur answer ⬇️⬇️
_________________________________
Let the numbers = 2x , 3x , 5x
Sum of their cubes = 54880
ACC.TO. STATEMENT:
(2x)^3 + (3x)^3 + (5x)^3 = 54880
8x^3 + 27x^3 + 125x^3 = 54880
160 x^3 = 54880
x^3 = 343
x = 7
So ,the numbers are 2x , 3x , 5x
▶️14 , 21 , 35 ......
_______________________________
HOPE IT HELPS U✌✌
Here is ur answer ⬇️⬇️
_________________________________
Let the numbers = 2x , 3x , 5x
Sum of their cubes = 54880
ACC.TO. STATEMENT:
(2x)^3 + (3x)^3 + (5x)^3 = 54880
8x^3 + 27x^3 + 125x^3 = 54880
160 x^3 = 54880
x^3 = 343
x = 7
So ,the numbers are 2x , 3x , 5x
▶️14 , 21 , 35 ......
_______________________________
HOPE IT HELPS U✌✌
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