Three numbers a,b,c are in G.P. if a,b, c-64 are in A.P and a,b-8, c-64 are in G.P,then the sum of numbers may be
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Answer:
is given that the product of the terms is 216, therefore,
r
a
×a×ar=216
⇒a
3
=216
⇒a
3
=6
3
⇒a=6.....(1)
It is also given that the sum of the terms is 21, therefore using equation 1 we have,
r
a
+a+ar=21
⇒
r
6
+6+6r=21
⇒
r
6
+6r=21−6
⇒6(
r
1
+r)=15
⇒
r
1+r
2
=
6
15
=
2
5
⇒2r
2
+2=5r
⇒2r
2
−5r+2=0
⇒2r
2
−4r−r+2=0
⇒2r(r−2)−1(r−2)=0
⇒(2r−1)(r−2)=0
⇒(2r−1)=0,(r−2)=0
⇒r=
2
1
,r=2
With a=6 and r=
2
1
, the three terms of G.P are as follows:
r
a
=
2
1
6
=6×2=12
a=6
ar=6×
2
1
=3
Thus, the terms are 12,6 and 3.
With a=6 and r=2, the three terms are:
r
a
=
2
6
=3
a=6
ar=6×2=12
Thus, the terms are 3,6 and 12.
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